What is the extreme f(x,y)=xy-2x-2y-x^2-y^2 ?

The extreme f(x,y)=xy-2x-2y-x^2-y^2 is Maximum(-2,-2)

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extreme f(x,y)=xy-2x-2y-x^2-y^2

extreme points

f (x, y) = x y - 2 x - 2 y - x^{2} - y^{2}

Maximum (- 2, - 2)

Solution steps

Find the critical points:

(- 2, - 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = 3

Check the sign of at each critical point

Check critical point

(- 2, - 2) :

Maximum

Maximum (- 2, - 2)

f (x) = x^{2} \cdot e^{- x}

y = x^{2} - 4 x

f (x, y) = \frac{x + y}{x ^{2} - y ^{2}}

f (x) = 3 x^{2} - 12 x + 9

f (x) = \frac{10}{3} x^{3} - x^{2} - 8 x + 48

What is the extreme f(x,y)=xy-2x-2y-x^2-y^2 ?
The extreme f(x,y)=xy-2x-2y-x^2-y^2 is Maximum(-2,-2)