What is the extreme f(x)=x^3-3x^2-9x+4 ?

The extreme f(x)=x^3-3x^2-9x+4 is Maximum(-1,9),Minimum(3,-23)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x^2-9x+4

extreme points

f (x) = x^{3} - 3 x^{2} - 9 x + 4

Maximum (- 1, 9), Minimum (3, - 23)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x^{2} - 9 x + 4 : 9

Maximum (- 1, 9)

Plug

x = 3

into

x^{3} - 3 x^{2} - 9 x + 4 : - 23

Minimum (3, - 23)

Maximum (- 1, 9), Minimum (3, - 23)

\frac{x}{ln ( x )}

f (x) = x^{3} - 3 x y - y^{2}

f (x) = x^{2} - 4 x + 2

x^{2} - 4 x + 5

f (x) = e^{- 3.5 x^{2}}

What is the extreme f(x)=x^3-3x^2-9x+4 ?
The extreme f(x)=x^3-3x^2-9x+4 is Maximum(-1,9),Minimum(3,-23)