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Popular >

extreme f(x)= 1/2 x^2+ln(1-x)+7

Solution

extreme points

f (x) = \frac{1}{2} x^{2} + ln (1 - x) + 7

Solution

None

Solution steps

f^{'} (x) = x - \frac{1}{- x + 1}

Find intervals:

None

None

Popular Examples

extreme f(x)=3x^4-24x^3+25 extreme points

f (x) = 3 x^{4} - 24 x^{3} + 25

extreme f(x,y)=4y^3+sqrt(x^2+y^2)extreme points

f (x, y) = 4 y^{3} + x^{2} + y^{2}

extreme f(x)= 1/3 x^3-2x^2-12x extreme points

f (x) = \frac{1}{3} x^{3} - 2 x^{2} - 12 x

extreme f(x)=-x^2+3x,0<= x<= 3 extreme points

f (x) = - x^{2} + 3 x, 0 \leq x \leq 3

extreme f(x)=x^3+3x^2-1 extreme points

f (x) = x^{3} + 3 x^{2} - 1

Frequently Asked Questions (FAQ)

What is the extreme f(x)= 1/2 x^2+ln(1-x)+7 ?
The extreme f(x)= 1/2 x^2+ln(1-x)+7 is None