What is the extreme f(x)=x^3-3x+10 ?

The extreme f(x)=x^3-3x+10 is Maximum(-1,12),Minimum(1,8)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x+10

extreme points

f (x) = x^{3} - 3 x + 10

Maximum (- 1, 12), Minimum (1, 8)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x + 10 : 12

Maximum (- 1, 12)

Plug

x = 1

into

x^{3} - 3 x + 10 : 8

Minimum (1, 8)

Maximum (- 1, 12), Minimum (1, 8)

f (x, y) = 2 y^{3} - 3 x y + x^{2} - 1

- \frac{cos ( 2 x )}{2} - 2 sin (x)

f (x) = 2 x^{3} - x^{2} - 4 x - 1

x 1 - x^{2}

f (x) = 2 x^{4} - 16 x^{2} + 3

What is the extreme f(x)=x^3-3x+10 ?
The extreme f(x)=x^3-3x+10 is Maximum(-1,12),Minimum(1,8)