What is the extreme f(x,y)=e^{-y}(x^2+y^2) ?

The extreme f(x,y)=e^{-y}(x^2+y^2) is Minimum(0,0),Saddle(0,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=e^{-y}(x^2+y^2)

extreme points

f (x, y) = e^{- y} (x^{2} + y^{2})

Minimum (0, 0), Saddle (0, 2)

Solution steps

Find the critical points:

(0, 0), (0, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - e^{- y} (- y^{2} + 4 y - x^{2} - 2)

D (x, y) = - 2 e^{- 2 y} x^{2} + 4 e^{- 2 y} + 2 e^{- 2 y} y^{2} - 8 e^{- 2 y} y

Check the sign of at each critical point

Check critical point

(0, 0) :

Minimum

Check critical point

(0, 2) :

Saddle

Minimum (0, 0), Saddle (0, 2)

f (x, y) = x^{3} + y^{3} - 6 x y

f (x) = 2 x + cos (2 x)

f (x) = \frac{1}{3} x^{3} - x^{2} - 3 x + 1

f (x) = \frac{1}{3} x^{3} - x^{2} - 3 x + 4

f (x) = x^{3} - 3 x + 3 x y^{2}

What is the extreme f(x,y)=e^{-y}(x^2+y^2) ?
The extreme f(x,y)=e^{-y}(x^2+y^2) is Minimum(0,0),Saddle(0,2)