What is the extreme f(x)=-(x+4)^3,-4<= x<=-3 ?

The extreme f(x)=-(x+4)^3,-4<= x<=-3 is Maximum(-4,0),Minimum(-3,-1)

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extreme f(x)=-(x+4)^3,-4<= x<=-3

extreme points

f (x) = - (x + 4)^{3}, - 4 \leq x \leq - 3

Maximum (- 4, 0), Minimum (- 3, - 1)

Solution steps

Find the critical points:

x = - 4, x = - 3

Domain of

- (x + 4)^{3}, - 4 \leq x \leq - 3 : - 4 \leq x \leq - 3

Find intervals:

Decreasing

: - 4 < x < - 3

Plug the extreme point

x = - 4

into

- (x + 4)^{3} \Rightarrow y = 0

Maximum (- 4, 0)

Plug the extreme point

x = - 3

into

- (x + 4)^{3} \Rightarrow y = - 1

Minimum (- 3, - 1)

Maximum (- 4, 0), Minimum (- 3, - 1)

f (x) = \frac{x ^{3}}{3} - \frac{7 x ^{2}}{2} + 10 x - 4

f (x) = \frac{4 x ^{2}}{x ^{2} - 4}

f (x) = x^{2} + 2 x + y^{2}

f (x, y) = 4 - x^{2} - y^{2}

f (x) = x^{2} + 4 x

What is the extreme f(x)=-(x+4)^3,-4<= x<=-3 ?
The extreme f(x)=-(x+4)^3,-4<= x<=-3 is Maximum(-4,0),Minimum(-3,-1)