What is the inverse of e^{(x^2-4)}-1 ?

The inverse of e^{(x^2-4)}-1 is sqrt(ln(x+1)+4),-sqrt(ln(x+1)+4)

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inverse of e^{(x^2-4)}-1

inverse

e^{(x^{2} - 4)} - 1

ln (x + 1) + 4, - ln (x + 1) + 4

Solution steps

y = e^{x^{2} - 4} - 1

Replace

x

with

y

x = e^{y^{2} - 4} - 1

Solve for

y, x = e^{y^{2} - 4} - 1

ln (x + 1) + 4, - ln (x + 1) + 4

4 x - 3 y = - 6

f (x) = \frac{12}{x - 1}

\frac{2}{3.3} x^{2} - 4 x + 6.6

cos (2) (x - \frac{π}{2})

f (x) = \frac{x + 2}{x - 4}

What is the inverse of e^{(x^2-4)}-1 ?
The inverse of e^{(x^2-4)}-1 is sqrt(ln(x+1)+4),-sqrt(ln(x+1)+4)