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Popular >

extreme f(x)=2x^2-4x

Solution

extreme points

f (x) = 2 x^{2} - 4 x

Solution

Minimum (1, - 2)

Solution steps

f^{'} (x) = 4 x - 4

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

2 x^{2} - 4 x : - 2

Minimum (1, - 2)

Popular Examples

extreme f(x)= 1/2 y^4-4xy+2x^4 extreme points

f (x) = \frac{1}{2} y^{4} - 4 x y + 2 x^{4}

extreme f(x)=12xy-x^3-y^3 extreme points

f (x) = 12 x y - x^{3} - y^{3}

extreme f(x,y)=338y^2+x^2-x^2y extreme points

f (x, y) = 338 y^{2} + x^{2} - x^{2} y

extreme f(x,y)=-x^2-y^2-1/2 x extreme points

f (x, y) = - x^{2} - y^{2} - \frac{1}{2} x

extreme f(x)=(-2)/(x^2-1)extreme points

f (x) = \frac{- 2}{x ^{2} - 1}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-4x ?
The extreme f(x)=2x^2-4x is Minimum(1,-2)