What is the extreme f(x)=-3x^3-9x^2 ?

The extreme f(x)=-3x^3-9x^2 is Minimum(-2,-12),Maximum(0,0)

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extreme f(x)=-3x^3-9x^2

extreme points

f (x) = - 3 x^{3} - 9 x^{2}

Minimum (- 2, - 12), Maximum (0, 0)

Solution steps

f^{'} (x) = - 9 x^{2} - 18 x

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < \infty

Plug

x = - 2

into

- 3 x^{3} - 9 x^{2} : - 12

Minimum (- 2, - 12)

Plug

x = 0

into

- 3 x^{3} - 9 x^{2} : 0

Maximum (0, 0)

Minimum (- 2, - 12), Maximum (0, 0)

f (x, y) = 4 x y - y^{4} - 2 x^{2}

f (x, y) = 2 x^{3} - 6 x^{2} + y^{3} + 21 y^{2}

x^{2} - 4 x + 3

f (x) = x^{3} + x^{2} - 5

f (x, y) = 25 - x^{2} - y^{2}

What is the extreme f(x)=-3x^3-9x^2 ?
The extreme f(x)=-3x^3-9x^2 is Minimum(-2,-12),Maximum(0,0)