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Popular >

extreme (3x^2)/(x^2-16)

Solution

extreme points

\frac{3 x ^{2}}{x ^{2} - 16}

Solution

Maximum (0, 0)

Solution steps

f^{'} (x) = - \frac{96 x}{( x ^{2} - 16 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < - 4,

Increasing

: - 4 < x < 0,

Decreasing

: 0 < x < 4,

Decreasing

: 4 < x < \infty

Plug

x = 0

into

\frac{3 x ^{2}}{x ^{2} - 16} : 0

Maximum (0, 0)

Popular Examples

extreme f(x)= x/(x^2+25)extreme points

f (x) = \frac{x}{x ^{2} + 25}

extreme f(x,y)=4-1/9 x^2-1/16 y^2 extreme points

f (x, y) = 4 - \frac{1}{9} x^{2} - \frac{1}{16} y^{2}

extreme f(x)=sqrt(ln(1/(x+y)))extreme points

f (x) = ln (\frac{1}{x + y})

extreme f(x)=x^2e^x[-3.1]extreme points

f (x) = x^{2} e^{x} [- 3.1]

extreme 1/(x^2-1)extreme points

\frac{1}{x ^{2} - 1}

Frequently Asked Questions (FAQ)

What is the extreme (3x^2)/(x^2-16) ?
The extreme (3x^2)/(x^2-16) is Maximum(0,0)