What is the extreme f(x)=(x^3)/3-5x^2+16x-100 ?

The extreme f(x)=(x^3)/3-5x^2+16x-100 is Maximum(2,-256/3),Minimum(8,-364/3)

Popular >

extreme f(x)=(x^3)/3-5x^2+16x-100

extreme points

f (x) = \frac{x ^{3}}{3} - 5 x^{2} + 16 x - 100

Maximum (2, - \frac{256}{3}), Minimum (8, - \frac{364}{3})

Solution steps

f^{'} (x) = x^{2} - 10 x + 16

Find intervals:

Increasing

: - \infty < x < 2,

Decreasing

: 2 < x < 8,

Increasing

: 8 < x < \infty

Plug

x = 2

into

\frac{x ^{3}}{3} - 5 x^{2} + 16 x - 100 : - \frac{256}{3}

Maximum (2, - \frac{256}{3})

Plug

x = 8

into

\frac{x ^{3}}{3} - 5 x^{2} + 16 x - 100 : - \frac{364}{3}

Minimum (8, - \frac{364}{3})

Maximum (2, - \frac{256}{3}), Minimum (8, - \frac{364}{3})

f (x, y) = x y^{2} - 9 x^{2} - 2 y^{2}

f (x) = x^{2} + 4 x - 2

f (x, y) = 3 x + 5 y

f (x) = x y (1 - x - y)

f (x) = x^{3} + 10 x^{2} + 8

What is the extreme f(x)=(x^3)/3-5x^2+16x-100 ?
The extreme f(x)=(x^3)/3-5x^2+16x-100 is Maximum(2,-256/3),Minimum(8,-364/3)