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Popular >

extreme f(x)=(x^2+1)^3

Solution

extreme points

f (x) = (x^{2} + 1)^{3}

Solution

Minimum (0, 1)

Solution steps

f^{'} (x) = 6 x (x^{2} + 1)^{2}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

(x^{2} + 1)^{3} : 1

Minimum (0, 1)

Popular Examples

extreme f(x)=x^2-12x extreme points

f (x) = x^{2} - 12 x

extreme f(x,y)= 1/3 x^3+2y^2-3x^2+5x-8y+4 extreme points

f (x, y) = \frac{1}{3} x^{3} + 2 y^{2} - 3 x^{2} + 5 x - 8 y + 4

extreme f(x)=x^2y-xy^2 extreme points

f (x) = x^{2} y - x y^{2}

extreme g(x,y)=x^2-3xy-y^2 extreme points

g (x, y) = x^{2} - 3 x y - y^{2}

extreme f(x,y)=x^3+xy+y^2 extreme points

f (x, y) = x^{3} + x y + y^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x^2+1)^3 ?
The extreme f(x)=(x^2+1)^3 is Minimum(0,1)