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Popular >

extreme f(x)=x^4-32x+4

Solution

extreme points

f (x) = x^{4} - 32 x + 4

Solution

Minimum (2, - 44)

Solution steps

f^{'} (x) = 4 x^{3} - 32

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{4} - 32 x + 4 : - 44

Minimum (2, - 44)

Popular Examples

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f (x, y) = 12 x y - x^{2} - 3 y^{2}

extreme f(x,y)=4xy^2-2x^2-16y^2 extreme points

f (x, y) = 4 x y^{2} - 2 x^{2} - 16 y^{2}

extreme f(x)=(3x+1)/(1-2x)extreme points

f (x) = \frac{3 x + 1}{1 - 2 x}

extreme f(x,y)=16x+12y-2x^2-3y^2 extreme points

f (x, y) = 16 x + 12 y - 2 x^{2} - 3 y^{2}

extreme f(x)=x^3-4x^2 extreme points

f (x) = x^{3} - 4 x^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4-32x+4 ?
The extreme f(x)=x^4-32x+4 is Minimum(2,-44)