What is the extreme f(x)=x^3-3x^2-24x+32 ?

The extreme f(x)=x^3-3x^2-24x+32 is Maximum(-2,60),Minimum(4,-48)

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extreme f(x)=x^3-3x^2-24x+32

extreme points

f (x) = x^{3} - 3 x^{2} - 24 x + 32

Maximum (- 2, 60), Minimum (4, - 48)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 24

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 2

into

x^{3} - 3 x^{2} - 24 x + 32 : 60

Maximum (- 2, 60)

Plug

x = 4

into

x^{3} - 3 x^{2} - 24 x + 32 : - 48

Minimum (4, - 48)

Maximum (- 2, 60), Minimum (4, - 48)

f (x, y) = 1 - 9 x^{2} - y^{2}

f (x) = x + cos (2 x)

f (x) = 4 x^{3} - 3 x^{2} - 6 x + 3, 0 \leq x \leq 10

f (x, y) = x^{2} - y^{2} - 2 x - 4 y - 4

f (x, y) = 4 x^{2} - 3 x y

What is the extreme f(x)=x^3-3x^2-24x+32 ?
The extreme f(x)=x^3-3x^2-24x+32 is Maximum(-2,60),Minimum(4,-48)