What is the extreme f(x)=xsqrt(7-x) ?

The extreme f(x)=xsqrt(7-x) is Maximum(14/3 ,(14sqrt(7))/(3sqrt(3))),Minimum(7,0)

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extreme f(x)=xsqrt(7-x)

extreme points

f (x) = x 7 - x

Maximum (\frac{14}{3}, \frac{14 7}{3 3}), Minimum (7, 0)

Solution steps

f^{'} (x) = \frac{- 3 x + 14}{2 7 - x}

Find intervals:

Increasing

: - \infty < x < \frac{14}{3},

Decreasing

: \frac{14}{3} < x < 7

Plug

x = \frac{14}{3}

into

x 7 - x : \frac{14 7}{3 3}

Maximum (\frac{14}{3}, \frac{14 7}{3 3})

Plug

x = 7

into

x 7 - x : 0

Minimum (7, 0)

Maximum (\frac{14}{3}, \frac{14 7}{3 3}), Minimum (7, 0)

y = 5 t - 2 u (t - 1) + 3 u (t - 5)

T (x, y) = 8 - x^{2} - 4 y^{2}

f (x) = \frac{x ^{2} - x + 1}{x - 1}

f (x, y) = (x - y) e^{- x^{2} - y^{2}}

\frac{d}{d x} (5 x^{2} y^{4} - 23 x y^{3} + 4 y^{5})

What is the extreme f(x)=xsqrt(7-x) ?
The extreme f(x)=xsqrt(7-x) is Maximum(14/3 ,(14sqrt(7))/(3sqrt(3))),Minimum(7,0)