What is the extreme f(x)=x^3-10x^2+33x-36 ?

The extreme f(x)=x^3-10x^2+33x-36 is Maximum(3,0),Minimum(11/3 ,-4/27)

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extreme f(x)=x^3-10x^2+33x-36

extreme points

f (x) = x^{3} - 10 x^{2} + 33 x - 36

Maximum (3, 0), Minimum (\frac{11}{3}, - \frac{4}{27})

Solution steps

f^{'} (x) = 3 x^{2} - 20 x + 33

Find intervals:

Increasing

: - \infty < x < 3,

Decreasing

: 3 < x < \frac{11}{3},

Increasing

: \frac{11}{3} < x < \infty

Plug

x = 3

into

x^{3} - 10 x^{2} + 33 x - 36 : 0

Maximum (3, 0)

Plug

x = \frac{11}{3}

into

x^{3} - 10 x^{2} + 33 x - 36 : - \frac{4}{27}

Minimum (\frac{11}{3}, - \frac{4}{27})

Maximum (3, 0), Minimum (\frac{11}{3}, - \frac{4}{27})

x^{x}

x^{4} - 6 x^{3}

f (x) = x^{\frac{2}{3}} (x^{2} - 4)

P (x, y) = 4 x^{2} - 100 y^{2}

f (x, y) = 3 x^{3} y - 2 x^{2} y^{2} + y^{3}

What is the extreme f(x)=x^3-10x^2+33x-36 ?
The extreme f(x)=x^3-10x^2+33x-36 is Maximum(3,0),Minimum(11/3 ,-4/27)