What is the extreme f(x)= 1/(x+2),-4<= x<= 1 ?

The extreme f(x)= 1/(x+2),-4<= x<= 1 is Maximum(-4,-1/2),Minimum(1, 1/3)

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extreme f(x)= 1/(x+2),-4<= x<= 1

extreme points

f (x) = \frac{1}{x + 2}, - 4 \leq x \leq 1

Maximum (- 4, - \frac{1}{2}), Minimum (1, \frac{1}{3})

Solution steps

Find the critical points:

x = - 4, x = 1

Domain of

\frac{1}{x + 2}, - 4 \leq x \leq 1 : - 4 \leq x < - 2 or - 2 < x \leq 1

Find intervals:

Decreasing

: - 4 < x < - 2,

Decreasing

: - 2 < x < 1

Plug the extreme point

x = - 4

into

\frac{1}{x + 2} \Rightarrow y = - \frac{1}{2}

Maximum (- 4, - \frac{1}{2})

Plug the extreme point

x = 1

into

\frac{1}{x + 2} \Rightarrow y = \frac{1}{3}

Minimum (1, \frac{1}{3})

Maximum (- 4, - \frac{1}{2}), Minimum (1, \frac{1}{3})

f (x, y) = e^{y} (y^{2} - x^{2})

f (x, y) = x^{2} + y^{2} - 2 x - 2 y + 2

f (x) = 2 x^{3} - 6 x^{2} - 18 x + 7

f (x, y) = 2 x - y + 2

f (x) = 3 x^{4} - 4 x^{3} - 8

What is the extreme f(x)= 1/(x+2),-4<= x<= 1 ?
The extreme f(x)= 1/(x+2),-4<= x<= 1 is Maximum(-4,-1/2),Minimum(1, 1/3)