What is the extreme (x^2-2x+2)/(x-1) ?

The extreme (x^2-2x+2)/(x-1) is Maximum(0,-2),Minimum(2,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme (x^2-2x+2)/(x-1)

extreme points

\frac{x ^{2} - 2 x + 2}{x - 1}

Maximum (0, - 2), Minimum (2, 2)

Solution steps

f^{'} (x) = \frac{x ^{2} - 2 x}{( x - 1 ) ^{2}}

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 1,

Decreasing

: 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

\frac{x ^{2} - 2 x + 2}{x - 1} : - 2

Maximum (0, - 2)

Plug

x = 2

into

\frac{x ^{2} - 2 x + 2}{x - 1} : 2

Minimum (2, 2)

Maximum (0, - 2), Minimum (2, 2)

f (x, y) = y^{3} + x^{2} - 6 x y + 3 x + 6 y - 7

f (x, y) = - x^{4} - y^{4} + 4 x y

x^{2} - 4

f (x) = 3 x^{3} - 2 x^{2} + 6

K (a, b) = 4 a + 9 ab

What is the extreme (x^2-2x+2)/(x-1) ?
The extreme (x^2-2x+2)/(x-1) is Maximum(0,-2),Minimum(2,2)