What is the extreme f(x)=-x^3+3x-7 ?

The extreme f(x)=-x^3+3x-7 is Minimum(-1,-9),Maximum(1,-5)

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extreme f(x)=-x^3+3x-7

extreme points

f (x) = - x^{3} + 3 x - 7

Minimum (- 1, - 9), Maximum (1, - 5)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x - 7 : - 9

Minimum (- 1, - 9)

Plug

x = 1

into

- x^{3} + 3 x - 7 : - 5

Maximum (1, - 5)

Minimum (- 1, - 9), Maximum (1, - 5)

f (x, y) = x^{2} + 4 y^{2} - 6 x + 16 y

f (x, y) = 8 x y - x^{3} - 4 y^{2}

f (x) = 5 x^{6} - 3 x^{4} + 2 x - 9

f (x, y) = x^{3} + y^{3} - 9 x y + 27

f (x) = 6 x^{2} ln (x)

What is the extreme f(x)=-x^3+3x-7 ?
The extreme f(x)=-x^3+3x-7 is Minimum(-1,-9),Maximum(1,-5)