What is the extreme f(x)=(2x^3)/3+3x^2-20x ?

The extreme f(x)=(2x^3)/3+3x^2-20x is Maximum(-5, 275/3),Minimum(2,-68/3)

Popular >

extreme f(x)=(2x^3)/3+3x^2-20x

extreme points

f (x) = \frac{2 x ^{3}}{3} + 3 x^{2} - 20 x

Maximum (- 5, \frac{275}{3}), Minimum (2, - \frac{68}{3})

Solution steps

f^{'} (x) = 2 x^{2} + 6 x - 20

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 5

into

\frac{2 x ^{3}}{3} + 3 x^{2} - 20 x : \frac{275}{3}

Maximum (- 5, \frac{275}{3})

Plug

x = 2

into

\frac{2 x ^{3}}{3} + 3 x^{2} - 20 x : - \frac{68}{3}

Minimum (2, - \frac{68}{3})

Maximum (- 5, \frac{275}{3}), Minimum (2, - \frac{68}{3})

f (x) = \frac{x - 2}{x ^{2}}

5 x^{2} - 2

f (x) = 4 - x^{2} - 4 y^{2}

f (x, y) = x^{3} + 2 x y + y^{2} - 5 x

f (x) = - x^{3} - 7 x^{2} - 16 x - 42

What is the extreme f(x)=(2x^3)/3+3x^2-20x ?
The extreme f(x)=(2x^3)/3+3x^2-20x is Maximum(-5, 275/3),Minimum(2,-68/3)