What is the extreme f(x)=x^3-6x^2-15x+10 ?

The extreme f(x)=x^3-6x^2-15x+10 is Maximum(-1,18),Minimum(5,-90)

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extreme f(x)=x^3-6x^2-15x+10

extreme points

f (x) = x^{3} - 6 x^{2} - 15 x + 10

Maximum (- 1, 18), Minimum (5, - 90)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x - 15

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 1

into

x^{3} - 6 x^{2} - 15 x + 10 : 18

Maximum (- 1, 18)

Plug

x = 5

into

x^{3} - 6 x^{2} - 15 x + 10 : - 90

Minimum (5, - 90)

Maximum (- 1, 18), Minimum (5, - 90)

f (x) = x^{4} - 32 x^{2} + 6

f (x) = \frac{x}{( x - 1 ) ^{2}}

f (x, y) = 2^{2} x^{4} + 2^{2} y^{4} - 4 x y + 16

f (x) = I x - 3 I - 2

f (x) = - x^{4} - 4 x^{3} + 7

What is the extreme f(x)=x^3-6x^2-15x+10 ?
The extreme f(x)=x^3-6x^2-15x+10 is Maximum(-1,18),Minimum(5,-90)