What is the extreme f(x)= x/(x^2-x+25) ?

The extreme f(x)= x/(x^2-x+25) is Minimum(-5,-1/11),Maximum(5, 1/9)

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extreme f(x)= x/(x^2-x+25)

extreme points

f (x) = \frac{x}{x ^{2} - x + 25}

Minimum (- 5, - \frac{1}{11}), Maximum (5, \frac{1}{9})

Solution steps

f^{'} (x) = \frac{- x ^{2} + 25}{( x ^{2} - x + 25 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 5,

Decreasing

: 5 < x < \infty

Plug

x = - 5

into

\frac{x}{x ^{2} - x + 25} : - \frac{1}{11}

Minimum (- 5, - \frac{1}{11})

Plug

x = 5

into

\frac{x}{x ^{2} - x + 25} : \frac{1}{9}

Maximum (5, \frac{1}{9})

Minimum (- 5, - \frac{1}{11}), Maximum (5, \frac{1}{9})

f (x) = \frac{y ^{2}}{y + x ^{2}}

f (x) = - 3 x^{2} + 5 x y - 2 y^{2} + x + y

f (x) = 2 x^{6} + 4 x^{3} - 6 x

f (x, y) = 50 x + 60 y

f (t) = 10 u (t)

What is the extreme f(x)= x/(x^2-x+25) ?
The extreme f(x)= x/(x^2-x+25) is Minimum(-5,-1/11),Maximum(5, 1/9)