What is the shift 4sin(3θ-1/3 pi)+1 ?

The shift 4sin(3θ-1/3 pi)+1 is Phase: pi/9 , Vertical:1

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shift 4sin(3θ-1/3 pi)+1

shift

4 sin (3 θ - \frac{1}{3} π) + 1

Phase : \frac{π}{9}, Vertical : 1

Solution steps

Simplify

4 sin (3 θ - \frac{1}{3} π) + 1 : 4 sin (3 θ - \frac{π}{3}) + 1

f (x) = 4 sin (3 θ - \frac{π}{3}) + 1

g (B x - C) = sin (3 θ - \frac{π}{3}), B = 3, C = \frac{π}{3}, D = 1

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{3}}{3}

\frac{π}{9}

The vertical shift

D

1

1

f (x) = (\frac{4}{10})^{x}

f (x) = \frac{x ^{2}}{x ^{2} - 4}

\frac{4 x - 11}{x - 9}

\frac{tan ( 2 x )}{x}

f (x) = \frac{2}{x}

What is the shift 4sin(3θ-1/3 pi)+1 ?
The shift 4sin(3θ-1/3 pi)+1 is Phase: pi/9 , Vertical:1