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Popular >

extreme f(x)=(-8)/(x^2-1)

Solution

extreme points

f (x) = \frac{- 8}{x ^{2} - 1}

Solution

Minimum (0, 8)

Solution steps

f^{'} (x) = \frac{16 x}{( x ^{2} - 1 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 0,

Increasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 0

into

\frac{- 8}{x ^{2} - 1} : 8

Minimum (0, 8)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=(-8)/(x^2-1) ?
The extreme f(x)=(-8)/(x^2-1) is Minimum(0,8)