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Popular >

extreme f(x)=4x^3-2x^2+x-1

Solution

extreme points

f (x) = 4 x^{3} - 2 x^{2} + x - 1

Solution

None

Solution steps

f^{'} (x) = 12 x^{2} - 4 x + 1

Find intervals:

None

None

Popular Examples

extreme f(x)=x^5-5x^4+8 extreme points

f (x) = x^{5} - 5 x^{4} + 8

extreme f(x)=(6x)/(x^2-49)extreme points

f (x) = \frac{6 x}{x ^{2} - 49}

extreme f(x)=2x^3-x^2+8x extreme points

f (x) = 2 x^{3} - x^{2} + 8 x

extreme f(x)=2x^3+3x^2-180x extreme points

f (x) = 2 x^{3} + 3 x^{2} - 180 x

extreme f(x)=sqrt(16-x^2-4y^2)extreme points

f (x) = 16 - x^{2} - 4 y^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^3-2x^2+x-1 ?
The extreme f(x)=4x^3-2x^2+x-1 is None