What is the extreme f(x)=x^3-3x^2-10 ?

The extreme f(x)=x^3-3x^2-10 is Maximum(0,-10),Minimum(2,-14)

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extreme f(x)=x^3-3x^2-10

extreme points

f (x) = x^{3} - 3 x^{2} - 10

Maximum (0, - 10), Minimum (2, - 14)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x

Find intervals:

Increasing

: - \infty < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

x^{3} - 3 x^{2} - 10 : - 10

Maximum (0, - 10)

Plug

x = 2

into

x^{3} - 3 x^{2} - 10 : - 14

Minimum (2, - 14)

Maximum (0, - 10), Minimum (2, - 14)

x 9 - x^{2}

f (x, y) = \frac{2 + x}{x - y ^{2}}

x e^{3 - \frac{x}{4}}

f (x) = \frac{( x ^{2} )}{x - 1}

f (x, y) = 2 x^{3} - 15 x^{2} + y^{3} + 6 y^{2}

What is the extreme f(x)=x^3-3x^2-10 ?
The extreme f(x)=x^3-3x^2-10 is Maximum(0,-10),Minimum(2,-14)