What is the extreme 3y^2-2y^3-3x^2+6xy ?

The extreme 3y^2-2y^3-3x^2+6xy is Saddle(0,0),Maximum(2,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme 3y^2-2y^3-3x^2+6xy

extreme points

3 y^{2} - 2 y^{3} - 3 x^{2} + 6 x y

Saddle (0, 0), Maximum (2, 2)

Solution steps

Find the critical points:

(0, 0), (2, 2)

\frac{\partial ^{2} f}{\partial y ^{2}} = - 6

D (y, x) = 72 y - 72

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Check critical point

(2, 2) :

Maximum

Saddle (0, 0), Maximum (2, 2)

\frac{5 x}{x ^{2} - 16}

f (x, y) = 3 x^{3} - 9 x y + 3 y^{3}

f (x) = 6 - 2 x

f (x) = x e^{- 7 x}

f (x) = x (x^{2} - 4)

What is the extreme 3y^2-2y^3-3x^2+6xy ?
The extreme 3y^2-2y^3-3x^2+6xy is Saddle(0,0),Maximum(2,2)