What is the extreme f(x)=x^3-6x^2+9x+8 ?

The extreme f(x)=x^3-6x^2+9x+8 is Maximum(1,12),Minimum(3,8)

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extreme f(x)=x^3-6x^2+9x+8

extreme points

f (x) = x^{3} - 6 x^{2} + 9 x + 8

Maximum (1, 12), Minimum (3, 8)

Solution steps

f^{'} (x) = 3 x^{2} - 12 x + 9

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = 1

into

x^{3} - 6 x^{2} + 9 x + 8 : 12

Maximum (1, 12)

Plug

x = 3

into

x^{3} - 6 x^{2} + 9 x + 8 : 8

Minimum (3, 8)

Maximum (1, 12), Minimum (3, 8)

f (x) = 2 x + cos (2 x), 0 < x < π

f (x, y) = x^{2} - 3 x y + 5 x - 2 y + 6 y^{2} + 8

f (x) = \frac{9 - x ^{2}}{x}

f (x) = 2 x^{2} - 64 ln (x)

f (x) = e^{x - y} (x^{2} - 2 y^{2})

What is the extreme f(x)=x^3-6x^2+9x+8 ?
The extreme f(x)=x^3-6x^2+9x+8 is Maximum(1,12),Minimum(3,8)