What is the extreme f(x)=x^4-8x^2+6 ?

The extreme f(x)=x^4-8x^2+6 is Minimum(-2,-10),Maximum(0,6),Minimum(2,-10)

Popular >

extreme f(x)=x^4-8x^2+6

extreme points

f (x) = x^{4} - 8 x^{2} + 6

Minimum (- 2, - 10), Maximum (0, 6), Minimum (2, - 10)

Solution steps

f^{'} (x) = 4 x^{3} - 16 x

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < 0,

Decreasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 2

into

x^{4} - 8 x^{2} + 6 : - 10

Minimum (- 2, - 10)

Plug

x = 0

into

x^{4} - 8 x^{2} + 6 : 6

Maximum (0, 6)

Plug

x = 2

into

x^{4} - 8 x^{2} + 6 : - 10

Minimum (2, - 10)

Minimum (- 2, - 10), Maximum (0, 6), Minimum (2, - 10)

f (x, y) = 4 x^{2} + y^{2} - 8 x + 6 y + 8

f (x) = ln (27 + 8 x^{3})

f (x) = x^{5} + 10 x^{4} + 25 x^{3}

f (x, y) = x \cdot y

f (x) = 3 - x - \frac{2}{x}

What is the extreme f(x)=x^4-8x^2+6 ?
The extreme f(x)=x^4-8x^2+6 is Minimum(-2,-10),Maximum(0,6),Minimum(2,-10)