What is the extreme f(x)=x^4-50x^2+9 ?

The extreme f(x)=x^4-50x^2+9 is Minimum(-5,-616),Maximum(0,9),Minimum(5,-616)

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extreme f(x)=x^4-50x^2+9

extreme points

f (x) = x^{4} - 50 x^{2} + 9

Minimum (- 5, - 616), Maximum (0, 9), Minimum (5, - 616)

Solution steps

f^{'} (x) = 4 x^{3} - 100 x

Find intervals:

Decreasing

: - \infty < x < - 5,

Increasing

: - 5 < x < 0,

Decreasing

: 0 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = - 5

into

x^{4} - 50 x^{2} + 9 : - 616

Minimum (- 5, - 616)

Plug

x = 0

into

x^{4} - 50 x^{2} + 9 : 9

Maximum (0, 9)

Plug

x = 5

into

x^{4} - 50 x^{2} + 9 : - 616

Minimum (5, - 616)

Minimum (- 5, - 616), Maximum (0, 9), Minimum (5, - 616)

f (x) = - 4 x^{2} + 8 x - 2, 0 \leq x \leq 3

f (x) = 2 x^{3} - 12 x^{2}

f (x, y) = x^{3} - 3 x + y^{3} + \frac{5}{2} y^{2} - 2 y

f (x) = sin (x) cos (x), 0 \leq x \leq π

f (x) = 3 x^{3} + 18 x^{2} - 45 x + 26

What is the extreme f(x)=x^4-50x^2+9 ?
The extreme f(x)=x^4-50x^2+9 is Minimum(-5,-616),Maximum(0,9),Minimum(5,-616)