What is the extreme f(x)=2x^4-4x^2 ?

The extreme f(x)=2x^4-4x^2 is Minimum(-1,-2),Maximum(0,0),Minimum(1,-2)

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extreme f(x)=2x^4-4x^2

extreme points

f (x) = 2 x^{4} - 4 x^{2}

Minimum (- 1, - 2), Maximum (0, 0), Minimum (1, - 2)

Solution steps

f^{'} (x) = 8 x^{3} - 8 x

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 0,

Decreasing

: 0 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

2 x^{4} - 4 x^{2} : - 2

Minimum (- 1, - 2)

Plug

x = 0

into

2 x^{4} - 4 x^{2} : 0

Maximum (0, 0)

Plug

x = 1

into

2 x^{4} - 4 x^{2} : - 2

Minimum (1, - 2)

Minimum (- 1, - 2), Maximum (0, 0), Minimum (1, - 2)

f (x) = 10 x - x^{2}

f (x) = 5 x - x^{2}

f (x, y) = x y^{2} + 3 x^{3} y - x y

f (x) = 12 x - 18

f (x) = 2 x + \frac{64}{x ^{2}}

What is the extreme f(x)=2x^4-4x^2 ?
The extreme f(x)=2x^4-4x^2 is Minimum(-1,-2),Maximum(0,0),Minimum(1,-2)