What is the extreme f(x)=2x^3-3x^2-12x+13 ?

The extreme f(x)=2x^3-3x^2-12x+13 is Maximum(-1,20),Minimum(2,-7)

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extreme f(x)=2x^3-3x^2-12x+13

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x + 13

Maximum (- 1, 20), Minimum (2, - 7)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 12

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 1

into

2 x^{3} - 3 x^{2} - 12 x + 13 : 20

Maximum (- 1, 20)

Plug

x = 2

into

2 x^{3} - 3 x^{2} - 12 x + 13 : - 7

Minimum (2, - 7)

Maximum (- 1, 20), Minimum (2, - 7)

f (x) = x^{3} + x^{2} - x - 1

f (x) = (x^{2} + 10) (9 - x^{2})

\frac{2 x}{x ^{2} - 4}

f (x, y) = 3 x^{4} + 3 y^{4} - x y

f (x) = \frac{x ^{2} - 3}{x + 2}

What is the extreme f(x)=2x^3-3x^2-12x+13 ?
The extreme f(x)=2x^3-3x^2-12x+13 is Maximum(-1,20),Minimum(2,-7)