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Popular >

extreme f(x)=\sqrt[3]{x^2}

Solution

extreme points

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = \frac{2 x}{3 ( x ^{2} ) ^{\frac{2}{3}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

Minimum (0, 0)

Popular Examples

extreme f(x)=2x^3-21x^2+60x,0<= x<= 6 extreme points

f (x) = 2 x^{3} - 21 x^{2} + 60 x, 0 \leq x \leq 6

extreme f(x)=e^{x^2-6x-1}extreme points

f (x) = e^{x^{2} - 6 x - 1}

extreme f(x)=4x^3-50x^2+150x extreme points

f (x) = 4 x^{3} - 50 x^{2} + 150 x

extreme f(x)=-x^2+6x extreme points

f (x) = - x^{2} + 6 x

extreme f(x)=(x-1)^3(x+1)^3 extreme points

f (x) = (x - 1)^{3} (x + 1)^{3}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=\sqrt[3]{x^2} ?
The extreme f(x)=\sqrt[3]{x^2} is Minimum(0,0)