What is the extreme f(x,y)=2x^2+3xy+y^2+ax+5 ?

The extreme f(x,y)=2x^2+3xy+y^2+ax+5 is Saddle(2a,-3a)

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extreme f(x,y)=2x^2+3xy+y^2+ax+5

extreme points

f (x, y) = 2 x^{2} + 3 x y + y^{2} + a x + 5

Saddle (2 a, - 3 a)

Solution steps

Find the critical points:

(2 a, - 3 a)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(2 a, - 3 a) :

Saddle

Saddle (2 a, - 3 a)

f (x) = 6 x

f (x) = 4 x ln (x)

f (x) = x^{2} + x y + y^{2} + 3 x - 3 y + 4

f (x, y) = x y + ln (x) + 32 y^{2}

f (x) = x (x - 1)^{2} (x - 2)^{3}

What is the extreme f(x,y)=2x^2+3xy+y^2+ax+5 ?
The extreme f(x,y)=2x^2+3xy+y^2+ax+5 is Saddle(2a,-3a)