What is the extreme f(x)=x^3+3x^2-9x+5 ?

The extreme f(x)=x^3+3x^2-9x+5 is Maximum(-3,32),Minimum(1,0)

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extreme f(x)=x^3+3x^2-9x+5

extreme points

f (x) = x^{3} + 3 x^{2} - 9 x + 5

Maximum (- 3, 32), Minimum (1, 0)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 x^{2} - 9 x + 5 : 32

Maximum (- 3, 32)

Plug

x = 1

into

x^{3} + 3 x^{2} - 9 x + 5 : 0

Minimum (1, 0)

Maximum (- 3, 32), Minimum (1, 0)

f (x) = 5 x^{3} + 2 x^{2} - 3 x

f (x) = \frac{x}{x ^{2} + y ^{2}}

f (x) = \frac{- 12 x ^{3} + x}{x}

\frac{e ^{x}}{1 - e ^{x}}

f (x, y) = x^{2} + 2 y^{2}

What is the extreme f(x)=x^3+3x^2-9x+5 ?
The extreme f(x)=x^3+3x^2-9x+5 is Maximum(-3,32),Minimum(1,0)