What is the extreme f(x)=2x^3+3x^2-36x+5 ?

The extreme f(x)=2x^3+3x^2-36x+5 is Maximum(-3,86),Minimum(2,-39)

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extreme f(x)=2x^3+3x^2-36x+5

extreme points

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 5

Maximum (- 3, 86), Minimum (2, - 39)

Solution steps

f^{'} (x) = 6 x^{2} + 6 x - 36

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 3

into

2 x^{3} + 3 x^{2} - 36 x + 5 : 86

Maximum (- 3, 86)

Plug

x = 2

into

2 x^{3} + 3 x^{2} - 36 x + 5 : - 39

Minimum (2, - 39)

Maximum (- 3, 86), Minimum (2, - 39)

f (x, y) = (x^{2} + y^{2}) e^{y^{2} - x^{2}}

f (x) = - ln (\frac{1}{x + y})

f (x) = 2 + 12 x + 3 x^{2} - 2 x^{3}

f (x, y) = 9 - x^{2} - 9 y^{2}

f (x) = x^{4} + 2 x^{3} - 2 x^{2} + 2

What is the extreme f(x)=2x^3+3x^2-36x+5 ?
The extreme f(x)=2x^3+3x^2-36x+5 is Maximum(-3,86),Minimum(2,-39)