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Popular >

extreme f(x)=-x^2+160x-400

Solution

extreme points

f (x) = - x^{2} + 160 x - 400

Solution

Maximum (80, 6000)

Solution steps

f^{'} (x) = - 2 x + 160

Find intervals:

Increasing

: - \infty < x < 80,

Decreasing

: 80 < x < \infty

Plug

x = 80

into

- x^{2} + 160 x - 400 : 6000

Maximum (80, 6000)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=-x^2+160x-400 ?
The extreme f(x)=-x^2+160x-400 is Maximum(80,6000)