What is the extreme f(x)=1-e^{-kx} ?

The extreme f(x)=1-e^{-kx} is Saddle(0,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=1-e^{-kx}

extreme points

f (x) = 1 - e^{- k x}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - e^{- x k} x^{2}

D (x, k) = 2 e^{- 2 x k} x k - e^{- 2 x k}

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x, y) = x^{2} - y^{2} - 2 x + 4 y + 6

\frac{1}{x + 1}

f (x) = x^{2} + 4 x + 4, - 4 \leq x \leq 0

f (x, y) = x^{2} y^{3} - 10 y + 15 x y^{2}

x^{2} + x y + y^{2} + 3 x - 3 y + 4