What is the extreme f(x)=x^3-9x^2+15x-7 ?

The extreme f(x)=x^3-9x^2+15x-7 is Maximum(1,0),Minimum(5,-32)

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extreme f(x)=x^3-9x^2+15x-7

extreme points

f (x) = x^{3} - 9 x^{2} + 15 x - 7

Maximum (1, 0), Minimum (5, - 32)

Solution steps

f^{'} (x) = 3 x^{2} - 18 x + 15

Find intervals:

Increasing

: - \infty < x < 1,

Decreasing

: 1 < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 1

into

x^{3} - 9 x^{2} + 15 x - 7 : 0

Maximum (1, 0)

Plug

x = 5

into

x^{3} - 9 x^{2} + 15 x - 7 : - 32

Minimum (5, - 32)

Maximum (1, 0), Minimum (5, - 32)

f (x) = 5 x^{4} - x^{5}

f (x) = \frac{1}{x} + ln (x), 0.5 \leq x \leq 4

f (x) = \frac{2 x - 3}{x} se

f (x) = \frac{x}{x ^{2} + 10 x + 21}

y = x + 1 - x

What is the extreme f(x)=x^3-9x^2+15x-7 ?
The extreme f(x)=x^3-9x^2+15x-7 is Maximum(1,0),Minimum(5,-32)