What is the extreme f(x)=x^3+3*x^2-9x+27 ?

The extreme f(x)=x^3+3*x^2-9x+27 is Maximum(-3,54),Minimum(1,22)

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extreme f(x)=x^3+3*x^2-9x+27

extreme points

f (x) = x^{3} + 3 \cdot x^{2} - 9 x + 27

Maximum (- 3, 54), Minimum (1, 22)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 9

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 3

into

x^{3} + 3 \cdot x^{2} - 9 x + 27 : 54

Maximum (- 3, 54)

Plug

x = 1

into

x^{3} + 3 \cdot x^{2} - 9 x + 27 : 22

Minimum (1, 22)

Maximum (- 3, 54), Minimum (1, 22)

f (x) = \frac{x ^{3}}{3} - 4 x^{2} + 7 x + 8

F (x, y) = - x^{3} + 6 x y - 3 y^{2} + 1

f (x y) = x^{3} + 3 y^{3} + 3 x^{2} + 3 y^{2} + 24

f (x, y) = - 6 + 2 x + 6 y - x^{2} - y^{2}

f (x, y) = ln (1 + x^{2} + y^{2})

What is the extreme f(x)=x^3+3*x^2-9x+27 ?
The extreme f(x)=x^3+3*x^2-9x+27 is Maximum(-3,54),Minimum(1,22)