What is the extreme f(x,y)=2x^3y^2+4xy+6 ?

The extreme f(x,y)=2x^3y^2+4xy+6 is None

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extreme f(x,y)=2x^3y^2+4xy+6

extreme points

f (x, y) = 2 x^{3} y^{2} + 4 x y + 6

None

Solution steps

Find the critical points:

None

2 x^{3} y^{2} + 4 x y + 6

has no critical points, therefore there are no extreme points

None

K (r, s) = 2 r - s

f (x) = x^{5} - 10 x^{4} + 25 x^{3}

1 + 6 x^{2} - x^{3}

f (x) = x - \frac{3}{2} x^{\frac{2}{3}}

f (x) = x^{4} - 8 x^{3} + 5

What is the extreme f(x,y)=2x^3y^2+4xy+6 ?
The extreme f(x,y)=2x^3y^2+4xy+6 is None