What is the extreme F(x,y)=x^3ln(y^2+1)-2y ?

The extreme F(x,y)=x^3ln(y^2+1)-2y is None

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extreme F(x,y)=x^3ln(y^2+1)-2y

extreme points

F (x, y) = x^{3} ln (y^{2} + 1) - 2 y

None

Solution steps

Find the critical points:

None

x^{3} ln (y^{2} + 1) - 2 y

has no critical points, therefore there are no extreme points

None

f (x) = 1 + 6 x^{2} - x^{3}

2 x + 10

f (x, y) = e^{- x^{2} - y^{2}}

f (x, y) = 72 y^{2} + x^{2} - x^{2} y

f (x, y) = x^{2} - 6 x y + y^{3} + 3 x + 6 y - 2

What is the extreme F(x,y)=x^3ln(y^2+1)-2y ?
The extreme F(x,y)=x^3ln(y^2+1)-2y is None