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Popular >

extreme f(x)=ln(5-3x^2)

Solution

extreme points

f (x) = ln (5 - 3 x^{2})

Solution

Maximum (0, ln (5))

Solution steps

f^{'} (x) = - \frac{6 x}{5 - 3 x ^{2}}

Find intervals:

Increasing

: - \frac{5}{3} < x < 0,

Decreasing

: 0 < x < \frac{5}{3}

Plug

x = 0

into

ln (5 - 3 x^{2}) : ln (5)

Maximum (0, ln (5))

Popular Examples

extreme f(x)=(x^3+3)/(2x^2-6x-4)extreme points

f (x) = \frac{x ^{3} + 3}{2 x ^{2} - 6 x - 4}

extreme f(x)=(x^3-2)/((x-1)^2)extreme points

f (x) = \frac{x ^{3} - 2}{( x - 1 ) ^{2}}

extreme f(x)= 3/(x+4)extreme points

f (x) = \frac{3}{x + 4}

extreme f(x,y)=((x+9)^2-1)(x^2-16)+200y^2+2 extreme points

f (x, y) = ((x + 9)^{2} - 1) (x^{2} - 16) + 200 y^{2} + 2

extreme f(x,y)=5xy-7x^2-y^2+3x-6y+2 extreme points

f (x, y) = 5 x y - 7 x^{2} - y^{2} + 3 x - 6 y + 2

Frequently Asked Questions (FAQ)

What is the extreme f(x)=ln(5-3x^2) ?
The extreme f(x)=ln(5-3x^2) is Maximum(0,ln(5))