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Popular >

extreme f(x)=2x^2-5x+3

Solution

extreme points

f (x) = 2 x^{2} - 5 x + 3

Solution

Minimum (\frac{5}{4}, - \frac{1}{8})

Solution steps

f^{'} (x) = 4 x - 5

Find intervals:

Decreasing

: - \infty < x < \frac{5}{4},

Increasing

: \frac{5}{4} < x < \infty

Plug

x = \frac{5}{4}

into

2 x^{2} - 5 x + 3 : - \frac{1}{8}

Minimum (\frac{5}{4}, - \frac{1}{8})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=2x^2-5x+3 ?
The extreme f(x)=2x^2-5x+3 is Minimum(5/4 ,-1/8)