What is the domain of f(x)=-sqrt(2x-2)+4 ?

The domain of f(x)=-sqrt(2x-2)+4 is x>= 1

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domain of f(x)=-sqrt(2x-2)+4

domain

f (x) = - 2 x - 2 + 4

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = - 6 sin (3 π x + 4) - 2

f (x) = 6 x^{2} + 6 x - 1

f (x) = \frac{1}{( x + 1 ) ^{2}}

f (x) = 11 - x

\frac{x ^{2} + 5 x + 6}{- 3 x - 6}

What is the domain of f(x)=-sqrt(2x-2)+4 ?
The domain of f(x)=-sqrt(2x-2)+4 is x>= 1