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Popular >

extreme f(x)=-2x^2-16x-39

Solution

extreme points

f (x) = - 2 x^{2} - 16 x - 39

Solution

Maximum (- 4, - 7)

Solution steps

f^{'} (x) = - 4 x - 16

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < \infty

Plug

x = - 4

into

- 2 x^{2} - 16 x - 39 : - 7

Maximum (- 4, - 7)

Popular Examples

extreme f(x)=ln(x^2+y^2-4)extreme points

f (x) = ln (x^{2} + y^{2} - 4)

extreme f(x,y)=x^3-y^3+43xy-7 extreme points

f (x, y) = x^{3} - y^{3} + 43 x y - 7

extreme f(x,y)=2^2*x^4+2^2*y^4-4*x*y+13 extreme points

f (x, y) = 2^{2} \cdot x^{4} + 2^{2} \cdot y^{4} - 4 \cdot x \cdot y + 13

extreme f(x)=(e^{-x})/((1+e^{-x))^2}extreme points

f (x) = \frac{e ^{- x}}{( 1 + e ^{- x} ) ^{2}}

extreme f(x)=((ln(x))^2)/x extreme points

f (x) = \frac{( ln ( x ) ) ^{2}}{x}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=-2x^2-16x-39 ?
The extreme f(x)=-2x^2-16x-39 is Maximum(-4,-7)