What is the domain of f(x)=sqrt(x^2-3x-10) ?

The domain of f(x)=sqrt(x^2-3x-10) is x = 5

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domain of f(x)=sqrt(x^2-3x-10)

domain

f (x) = x^{2} - 3 x - 10

x \leq - 2 or x \geq 5

Interval Notation

(- \infty, - 2] \cup [5, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 5

The function domain

x \leq - 2 or x \geq 5

f (x) = 7 x - 8

20 x - 24 y = - 144

f (x) = \frac{1}{4} x - 1

y = arccos (2)

x - 8

What is the domain of f(x)=sqrt(x^2-3x-10) ?
The domain of f(x)=sqrt(x^2-3x-10) is x<=-2\lor x>= 5