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Popular >

extreme f(x)=x^4+3x^2

Solution

extreme points

f (x) = x^{4} + 3 x^{2}

Solution

Minimum (0, 0)

Solution steps

f^{'} (x) = 4 x^{3} + 6 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{4} + 3 x^{2} : 0

Minimum (0, 0)

Popular Examples

extreme f(x)=(x^2-3x)/(x^2+1)extreme points

f (x) = \frac{x ^{2} - 3 x}{x ^{2} + 1}

extreme f(x,y)=sqrt(-ln(1/(x+y)))extreme points

f (x, y) = - ln (\frac{1}{x + y})

extreme 4x^5-5x^4 extreme points

4 x^{5} - 5 x^{4}

extreme f(x)=(x^2-3x+5)e^{(-x)/3}extreme points

f (x) = (x^{2} - 3 x + 5) e^{\frac{- x}{3}}

extreme f(x)=4x^2+8x+4y^2+4 extreme points

f (x) = 4 x^{2} + 8 x + 4 y^{2} + 4

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4+3x^2 ?
The extreme f(x)=x^4+3x^2 is Minimum(0,0)