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Popular >

extreme f(x)=x^2+8x+17

Solution

extreme points

f (x) = x^{2} + 8 x + 17

Solution

Minimum (- 4, 1)

Solution steps

f^{'} (x) = 2 x + 8

Find intervals:

Decreasing

: - \infty < x < - 4,

Increasing

: - 4 < x < \infty

Plug

x = - 4

into

x^{2} + 8 x + 17 : 1

Minimum (- 4, 1)

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+8x+17 ?
The extreme f(x)=x^2+8x+17 is Minimum(-4,1)