What is the extreme f(x)=x^4-2x^3-x^2-4x+3 ?

The extreme f(x)=x^4-2x^3-x^2-4x+3 is Minimum(2,-9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^4-2x^3-x^2-4x+3

extreme points

f (x) = x^{4} - 2 x^{3} - x^{2} - 4 x + 3

Minimum (2, - 9)

Solution steps

f^{'} (x) = 4 x^{3} - 6 x^{2} - 2 x - 4

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 2

into

x^{4} - 2 x^{3} - x^{2} - 4 x + 3 : - 9

Minimum (2, - 9)

f (x) = \frac{2}{3} x^{3} - x^{2} - 12 x + 3

y = x^{4} + 4 x^{3} - 2

f (x) = cos (\frac{2 π}{3} x)

P (x, y) = 8 x + 10 y - 1 (x^{2} + x y + y^{2}) - 10000

f (x, y) = 3 x^{4} + 8 x^{3} - 18 x^{2} + 6 y^{2} + 12 y - 4

What is the extreme f(x)=x^4-2x^3-x^2-4x+3 ?
The extreme f(x)=x^4-2x^3-x^2-4x+3 is Minimum(2,-9)